- This topic has 8 replies, 6 voices, and was last updated Jul-178:39 pm by
CFA_anon.
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Up::4
My approach was to first memorize the correlation formula, then the correlation version of the portfolio sd formula. Also, I have an old habit of converting all variances to sd before attempting to solve anything. Beyond that, it just took a lot of ink and repetition.
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Up::4
@microeconomist thanks for useful thought. Only problem I have is when you’re given correlation or covariance between A and B, obviously know how to convert correlation to covariance and vice versa given the standard deviations, issue is converting the rest of the formula given radical, etc
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Up::3
So in this case you need to square the weights (as always), but don’t need to square the variances, you then take the square roots of both variances to get the standard deviations in the final part of the equation and 1 is your correlation number, but you then take the square root of the whole enchilada…i.e. [(0.4)^2(0.25)+(0.6)^2(0.4)+2(0.4)(0.6)1(0.25)^0.5(0.4)^0.5]^0.5….0.5795
@CFA_redemption_12713
Remember that the square root of the variance is the standard deviation. The formulas above all use the standard deviation. That’s why they didn’t square the variances in the first part of the formula.What I do is always stick to the standard deviations and use them in the formulas.
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Up::2
If you could memorise the 2 formulas below you should be good.
1. The variance of a portfolio -> w1^2 * SD1^2 + w2^2 * SD2^2 + 2w1 * w2 * r * SD1 * SD2.
2. The formula for correlation (r = Cov / SD1 * SD2) in case they only give you the Covariance.Also, if you’re very comfortable with the formula and don’t mind using shortcuts.
Notice the last part of the formula goes like this –> 2 * w1 * w2 * r * SD1 * SD2 ?
If the covariance is given you could just do 2 * w1 * w2 * Cov. That way you could save some time since you are not calculating to obtain correlation and then multiply by both the standard deviation (SD).
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Up::1
So in this case you need to square the weights (as always), but don’t need to square the variances, you then take the square roots of both variances to get the standard deviations in the final part of the equation and 1 is your correlation number, but you then take the square root of the whole enchilada…i.e. [(0.4)^2(0.25)+(0.6)^2(0.4)+2(0.4)(0.6)1(0.25)^0.5(0.4)^0.5]^0.5….0.5795
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Up::1
@Lagarta I think if it’s perfectly positive correlated you simply take the weighted average of the Std. Devations and don’t have to do the complex calculation. In case one has a Std. Dev. of 0 you only take Std. Dev. x Weight for the other one.
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Up::0
First Term: (.4)^2 * (.25) = .04
Second Term: (.6)^2 * (.4) = .144
Third Term: 2 * (1) * (.4) * (.6) * (.5) * (.6324555) = .15178932
Added together: .33578932= variancesqrt(.33578932) = .57947331
OR
perfectly positively correlated means NO CORRELATION EFFECT TERM! 🙂
so
.4(stdev of A) + .6 (stdev of B) = Stdev of portfolio
.4(.5) + .6(.6324555) = .57947331So… A should be your answer
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