- This topic has 4 replies, 2 voices, and was last updated Mar-198:59 pm by
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Up7
No drama – I’ve worked it out!
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Up4
Thanks Artyeasel – much appreciated!
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Up2
For 2(1+g)^5=3, I would deduce using algebra, i.e. g = 1-(3/2)^(1/5)
So my keypresses would be [1.5] [Yx] [.2] [=] [1] [-] [Ans] [=] yielding 1.08.For the 20 year bond: yes, these questions crop up all the time, and there is a fast way to calculate it. There is already a great example in the BA II Plus guide book that you can get from 300 Hours. I’ll share a screenshot here (@christine let me know if this isn’t cool), but I’d recommend getting it as it probably can help you a lot more: http://www.300hours.com/ba-ii-plus-guide/#.WLfa_RKLTOQ
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Up2
Sorry in terms of the bond question how would you solve for r the following on the calculator
98 = 10/(1+r) + 10/(1+r)^2 + 110/(1+r)^3
I cant see it in the BA11 manual however it is coming up a lot in my current readings
thanks!
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