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Hi @rogileiza,
I understand that the formulas to get the justified trailing and leading multiples are counter intuitive. You’d think that the leading multiples would have the (1+g) and the trailing would not have the growth factor. However, it is backwards. Below are the derivations using the GGM:
justified trailing P0/E0=(1-b)(1+g)/(r-g)
justified leading P0/E1=(1-b)/(r-g)
Using the Gordon Growth Model:
justified trailing
P0=D0(1+g)/(r-g) using the GGM – then divide everything by E0
P0/E0=(D0/E0)(1+g)/(r-g) – D0/E0 = Dividend payout = (1-b) at time=0
Then – P0/E0=(1-b)(1+g)/(r-g)
leading trailing
P0=D1/(r-g) using the GGM – then divide everything by E1
P0/E1= (D1/E1)/(r-g) – D1/E1 = dividend payout at time=1
Then – P0/E1=(1-b)/(r-g)